Have you read about Coulomb's law? If not, it's time you did.
F = k*Q1*Q2/R^2
In your case, Q1 = -Q2 = 2.0*10^-6 Coulombs
R = 5.0*10^-2 meters
k is the "Coulomb constant",
8.99*10^9 N*m^2*/C^2
Solve for F in Newtons.
The force will be attractive since the charges have opposite sign.
What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? Show your work. (µC = 1.0 × 10–6 C)
1 answer