What is the electric field at a point midway between a -7.34 micro coulombs and a +4.49 micro coulombs charge apart 31.5m apart?

Answer 1

E=E₁+E₂=k|q₁|/(d/2)²+ k|q₂|/(d/2)²=
k/(d/2)²{ |q₁|+ q₂}=
=9•10⁹(7.34+4.49) •10⁻⁶/0.1575=
=6.76•10⁵V/m (directed to the negative charge)