60 cm or 80 cm ?????
If 80 cm =0.8 m , then
F = k•q1•q2/r² =
=9•10^9•40•10^-6•20•10^-6/0.8^2 = ...
what is the electric field at the position 20 cm from Q2 and 60 cm from Q1?
Q2=40 micro coulombs
Q1=20 micro coulombs
Q2 and Q1 are separated by 80 cm
4 answers
no elena i believe quinton is looking for the electric field positions of Q2 and Q1 separately at different distances from each respectively
Sorry.
E = k•q/r^2
E1 = k•q1/r1^2 = 9•10^9•40•10^-6/(0.2)^2 =6•10^6 V/m,
E2 = k•q2/r2^2 = 9•10^9•60•10^-6/(0.6)^2 = 1.5•10^6 V/m,
E =E1 – E2 = 4.5•10^6 V/m.
E = k•q/r^2
E1 = k•q1/r1^2 = 9•10^9•40•10^-6/(0.2)^2 =6•10^6 V/m,
E2 = k•q2/r2^2 = 9•10^9•60•10^-6/(0.6)^2 = 1.5•10^6 V/m,
E =E1 – E2 = 4.5•10^6 V/m.
thank you very much guys..i really appreciate it.