The domain of a square root function is all real numbers that make the radicand (the expression under the square root) non-negative. In this case, the radicand is 3x + 9.
To find the domain, set 3x + 9 greater than or equal to 0:
3x + 9 ≥ 0
3x ≥ -9
x ≥ -3
So, the domain of the function y = √(3x + 9) is all real numbers greater than or equal to -3.
What is the domain of the function?
y= root of 3x+9
1 answer
1 answer