how do you find the domain of the function::

14/(x^2 - 361) <-- this is all under a square root..

i have attempted this so many times and have not found the correct answer yet. how do i solve the domain when it is a square root function with a denominator???? please help!

thanks

1 answer

Two conditions are the problem here:
1. We cannot divide by zero
2. We cannot take the square root of a negative.

so 14/√(x^2 - 361)
= 14/√[(x+19)(x-19)]
so clearly x cannot be ± 19

secondly, wouldn't the number under the root sign be negative for all values between 1- and +19

so the domain is
x > 19 OR x < -19 , x is a real number.
Similar Questions
  1. 2. The function f is defined as followsf(x)={4+2x if x<0 {x^2 if x>0 a) Find the domain of the function b) Locate any intercepts
    1. answers icon 0 answers
    1. answers icon 1 answer
  2. Find the requested function and state its domain:f(x)= 4x+3 g(x)=4x-5 Find f/g and its domain. So I did 4x+3/4x-5, so the 4x's
    1. answers icon 0 answers
  3. Find the requested function and state its domain:f(x)= 4x+3 g(x)=4x-5 Find f/g and its domain. So I did 4x+3/4x-5, so the 4x's
    1. answers icon 1 answer
more similar questions