What is the distance between the parallel lines having equations 2x+2y=16 and x+y=0?

Question

I'm getting 2 as my answer but the answer is supposed to be 4√2

Answer 1

find slope of perpendicular
original is slope = -1
so slope of perpendicular is
-1/-1 = 1

pick a point on line 2, like (0,0)
then equation of perpendicular through that point is
y = x (just to make it east)
where does y = x hit the first line?
2 x + 2 x = 16
x = 4
then y = 4
so
distance form(0,0) to (4,4)
sqrt (4^2 + 4^2 ) = sqrt (2*16)
= 4 sqrt 2

Answer 2

Hey, Damon, can you please look at my reply on my problem?

Answer 3

Beats me Ryan

Answer 4

thanks!