What is the derivative of the fifth root of x^3?

4 answers

if y = (x^3)^(1/5)
= x^(3/5)

we would have dy/dx = (3/5)x^(3/5 - 1) = (3/5) x^(-2/5)
fifth root of x^3 = x(3/5)

derivative x^(3/5) = 3/5 x^(-2/5) = 3/5 *[5th root (x^-2)]
Thanks, i get it now
y = (x^3)^(1/5)
Using the chain rule,
y' = 1/5 (x^3)(-4/5) * 3x^2 = 3/5 x^(-12/5 + 2) = 3/5 x^(-2/5)
Similar Questions
    1. answers icon 1 answer
  1. How do i find the derivative off(t)= 20- 30/rooot 9 + t^2 heres how i did it f'(x)= 20' - 30/root(9+t^2) ' = 0 - 30/root(9+t^2)
    1. answers icon 0 answers
  2. find derivitive of 1/square root of x1/square root of x = x^(-1/2) The derivative is -1/2 x^(-3/2) can you keep going on the
    1. answers icon 0 answers
  3. Find the derivative** (sq root) y = (square root) x + (2nd sq root) x + (3rd sq root) x ** All the x's is under three sq roots
    1. answers icon 2 answers
more similar questions