Find the derivative

** (sq root)

y = (square root) x + (2nd sq root) x +
(3rd sq root) x

** All the x's is under three sq roots

y' = 1/2(sq rt) x + 1/(sq rt) x +
3/2(sq rt) x

Is this right?

2 answers

Go on: wolframalpha dot com

When page be open in rectangle type:

derivative your expresion

and click option =

After few seconds when you see result click option:

Show steps

If square root) x + (2nd sq root) x +
(3rd sq root) x

mean

sqrt(x )+2*sqrt(x)+3*sqrt(x)

type:

derivative sqrt(x )+ 2* sqrt(x)+3*sqrt(x)

and click option =

then

Show steps

On wolfram alpha dot com you can practice any kind ofCalculus
ok thank you
Similar Questions
  1. Identify Roots Quick Check5 of 55 of 5 Items Question Find the square root of 128.(1 point) Responses √64 x √2 start root 64
    1. answers icon 1 answer
  2. Add and Subtract Radicals Quick CheckMath 8 Q2 (Pre-Algebra) / Roots and Irrational Numbers add 2 square root 21 + 3 square root
    1. answers icon 1 answer
  3. Add and Subtract Radicals Quick CheckMath 8 Q2 (Pre-Algebra) / Roots and Irrational Numbers add 3 square root 21 + 7 square root
    1. answers icon 1 answer
  4. Express in simplest radical form.square root of, 3, x, end square root 3x ​ Answer Multiple Choice Answers square root of, 3,
    1. answers icon 1 answer
more similar questions