I think you need to convert the moles of sodium phosphate into grams of sodium phosphate. Then use that and divide by 300g of H20. Multiply the number that you get by 100, and it should give you the concentration in percentage mass of sodium phosphate in the ammount of water given 300g.
so,
0.250 mol x 119.98 g/mol= ____g NaH2PO4
Then divide that _____g NaH2PO4 found by 300g of H2O.
______g NaH2PO4 / 300g H2O x 100= ______% by mass concentration.
check me on this of course.
what is the concentration in percentage by mass when 0.250 moles of sodium phosphate is dissolved in 300 grams of water
2 answers
My thoughts on this are as follows:
Na3PO4 = sodium phosphate has a molar mass of 163.941.
0.25 moles x (1 mol Na3PO4/163.941) = 40.985 grams Na3PO4.
%Na3PO4 = (g solute/total mass soln)*100 =
(40.985/40.985+300)*100 =
12 something %. Check my work.
Na3PO4 = sodium phosphate has a molar mass of 163.941.
0.25 moles x (1 mol Na3PO4/163.941) = 40.985 grams Na3PO4.
%Na3PO4 = (g solute/total mass soln)*100 =
(40.985/40.985+300)*100 =
12 something %. Check my work.