Asked by Kristen
35 grams of sodium phosphate are mixed with enough water to make 3.5L of solution having a densityof 1.045g/mol. Find the concentration of sodium phosphate in ppm.
Using the same information, find the molarity of the sodium and phosphate ions.
Using the same information, find the molarity of the sodium and phosphate ions.
Answers
Answered by
DrBob222
second part:
moles Na3PO4 = grams/molar mass
M = moles/L soln
first part:
mass soln = 3,500 mL x 1.045 g/mL = about 3657.5 g
(Note: I think you meant to type 1.045 g/mL for the density and not g/mol).
So the solution is 35 g in 3657.5 g
That is 35/3657.5 = about 0.0096 g/g (but you need to do it more accurately). Multiply both numerator an denominator by 1E6 to obtain ppm.
moles Na3PO4 = grams/molar mass
M = moles/L soln
first part:
mass soln = 3,500 mL x 1.045 g/mL = about 3657.5 g
(Note: I think you meant to type 1.045 g/mL for the density and not g/mol).
So the solution is 35 g in 3657.5 g
That is 35/3657.5 = about 0.0096 g/g (but you need to do it more accurately). Multiply both numerator an denominator by 1E6 to obtain ppm.
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