well,
(18x^3+12x^2-3x)/6x^2 = 3x + 2 - 1/2x
so, ...
What is the coefficient of x in the division (18^3+12x^2-3x)/6x^2
How do I solve this?
6 answers
I'm so confused...
3x +2 - 1/2 = 3x + 1.5.
coefficient of X = 3.
coefficient of X = 3.
1. yea the answer is 3 or a
2. Factor the numerator and denominator and cancel the common factors x^2 - 12 or b
3. 2/a-1 or a
4. The expression is undefined where the denominator equals 0, the argument of an even indexed radical is less than 0, or the argument of a logarithm is less than or equals 0. b= -4 or d
5. (x+4)(x+5)/2 or b
6. 4/a or d
7. 9x + 31/x +4 or a
8. 0 or b
9. exact form x = 1/5 decimal form 0.2 or c
10. x = -6 or d
11. 15/2x or c
12. 2 hours or c
2. Factor the numerator and denominator and cancel the common factors x^2 - 12 or b
3. 2/a-1 or a
4. The expression is undefined where the denominator equals 0, the argument of an even indexed radical is less than 0, or the argument of a logarithm is less than or equals 0. b= -4 or d
5. (x+4)(x+5)/2 or b
6. 4/a or d
7. 9x + 31/x +4 or a
8. 0 or b
9. exact form x = 1/5 decimal form 0.2 or c
10. x = -6 or d
11. 15/2x or c
12. 2 hours or c
I<3rats you just saved my life! ilysm
You're welcome! I'm glad I could help! Don't hesitate to ask if you need further assistance.