molality = mols/kg solvent.
Solve for molality.
delta T = Kb*molality
Solve for delta T.
Add delta T + normal boiling point to obtain new boiling point.
what is the boiling point that contains 3.15 moles of ethylene C2H6O2 and 250.0g of H2O? answer should end in degree's celcius
a) 1.03 C
b) 93.55 C
c) 106.45 C
d) 6.45 C
e) 103.44 C
2 answers
3.15 mol / 0.250 kg = 12.6 mol/kg or 12.6 molal
The boiling point of a solution is
Tb = Tb(H2O) + deltaT = 100ยบ + deltaT
deltaT = Kb*m = (0.512deg.kg/mol)(12.6mol/kg)
NOTE: C2H6O2 is not ethylene. It may be
CH3-O-O-CH3 whose solubility could not be 12.6molal. It is a bad question. The solution given gives the most likely *expected* answer.
The boiling point of a solution is
Tb = Tb(H2O) + deltaT = 100ยบ + deltaT
deltaT = Kb*m = (0.512deg.kg/mol)(12.6mol/kg)
NOTE: C2H6O2 is not ethylene. It may be
CH3-O-O-CH3 whose solubility could not be 12.6molal. It is a bad question. The solution given gives the most likely *expected* answer.
2 answers