molality = moles/kg
Solve for molality.
delta T = Kb*molality
Solve for delta T.
Add to normal boiling point.
What is the boiling point of each solution?
a).50mol glucose in 1000g H2O
b)1.50mol NaCl in 1000g H2O
3 answers
0.50mol NaCl in1000gH2o
a. a. (T-100°C)= 0.512°C /molal x 0.50 mol/ 1.00 kg
T=100°C + 0.256°C = 100.256°C
T=100°C + 0.256°C = 100.256°C