What is the area of triangle ABC if a = 19, b = 14, and c = 23?

Answer 1

I would use Heron's Formula

area = √(s(s-a)(s-b)(s-c)) , where s = (a+b+c)/2

check your work with this

http://www.csgnetwork.com/areacalc.html

Answer 2

use Heron's formula, or use law of sines/cosines to determine one of the angles. then the area is 1/2 ab*sinC