Asked by Bob
What is the approximate ΔH in kJ for the following reaction as written:
2NH3(g) --> 3H2(g) + N2(g)
Careful, what kind of bond does the nitrogen molecule make?
2NH3(g) --> 3H2(g) + N2(g)
Careful, what kind of bond does the nitrogen molecule make?
Answers
Answered by
DrBob222
Frankly I don't see that the kind of bond N2 makes is relevant.
dHrxn = (n*dHformation products) - (n*dHf reactants)
Look up the dH formation for products and reactants and solve for dHrxn.
Hint in solving: dHformation H2 and dH formation N2 are zero by definition.
dHrxn = (n*dHformation products) - (n*dHf reactants)
Look up the dH formation for products and reactants and solve for dHrxn.
Hint in solving: dHformation H2 and dH formation N2 are zero by definition.
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