Asked by Helen
At 450oC, the equilibrium constant Kc for the Haber-Bosch synthesis of ammonia is 0.16 for the reaction writeten as 3H2(g) + N2 (g)--><--2NH3(g) calculate the value of Kc for the same reaction written as 3/2H2(g) + 1/2N2(g)-->--<NH3(g)
Answers
Answered by
DrBob222
3H2 + N2 ==> 2NH3 with Kc= 0.16
3/2H2 + 1/2N2 ==> NH3 is just 1/2 of the first equation; therefore, K'c = sqrt Kc or sqrt (0.16).
3/2H2 + 1/2N2 ==> NH3 is just 1/2 of the first equation; therefore, K'c = sqrt Kc or sqrt (0.16).
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.