What is the anode and cathode of this problem?

Question

A chemist wishes to determine the concentration of CrO4-2 ions electrochemically. A cell is constructed consisting of saturated calomel electrode (SCE) and a silver wire coated with Ag2CrO4. The SCE is composed of mercury in contact with a saturated solution of calomel (Hg2Cl2). The electrolyte solution in the half-cell is saturated KCl. The E°cell of the SCE half-cell is +0.242 V with respect to the standard hydrogen electrode. The half-reaction for the reduction of Ag2CrO4 is shown below. (15 points)

Ag2CrO4(s) + 2e- 2Ag(s) + CrO4-2(aq) E°cell = 0.446 V

I drew the SCE and AgCr is the wire, KCL is the electrolyte solution. There is Hg in contact with a saturated solution of calomel(HgCl).

I said that Hg2Cl2 acts as the cathode and anode? Is that right.

plz. Answer this question fully.

Ag2CrO4(s)  +  2e-    2Ag(s)  +  CrO4-2(aq)	E°cell  =  0.446 V

I drew the SCE and AgCr is the wire, KCL is the electrolyte solution. There is Hg in contact with a saturated solution of calomel(HgCl).

I said that Hg2Cl2 acts as the cathode and anode? Is that right.

plz. Answer this question fully.

Andrew · Answer

I said that Hg2Cl2 acted as both the anode and cathode?