Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Write chemical equations to represent the cathode, anode, and net cell reactions. 1) Cd | Cd(NO3)2 || Ag(NO3)2 | Ag Reduction a...Asked by Alex
Write chemical equations to represent the cathode, anode, and net cell reactions.
1) Cd | Cd(NO3)2 || Ag(NO3)2 | Ag
Reduction at Cathode: Cd2+ + 2e- ---> Cd
Oxidation at Anode: [Ag ---> Ag+ + e-] x2
Cd2+ + 2Ag ---> Cd + 2Ag2+
2) Pt | IO3-,H+ || Zn2+ | Zn
Reduction at Cathode: 2IO3- + 12H+ + 10e- ---> I2 + 6H2O
Oxidation at Anode: [Zn ---> Zn2+ + 2e-] x 5
2IO3- + 12H+ + Zn ---> I2 + 6H2O + Zn2+
1) Cd | Cd(NO3)2 || Ag(NO3)2 | Ag
Reduction at Cathode: Cd2+ + 2e- ---> Cd
Oxidation at Anode: [Ag ---> Ag+ + e-] x2
Cd2+ + 2Ag ---> Cd + 2Ag2+
2) Pt | IO3-,H+ || Zn2+ | Zn
Reduction at Cathode: 2IO3- + 12H+ + 10e- ---> I2 + 6H2O
Oxidation at Anode: [Zn ---> Zn2+ + 2e-] x 5
2IO3- + 12H+ + Zn ---> I2 + 6H2O + Zn2+
Answers
Answered by
DrBob222
For #1, have you done the voltage, Ecell?
Is this reaction to occur spontaneously?
If so, isn't what you show as the cell reaction a negative voltage? (The silver ion should be Ag^+.
The second equation isn't multiplied by 5 for Zn.
Is this reaction to occur spontaneously?
If so, isn't what you show as the cell reaction a negative voltage? (The silver ion should be Ag^+.
The second equation isn't multiplied by 5 for Zn.
Answered by
Alex
1) Cd | Cd(NO3)2 || Ag(NO3)2 | Ag
Reduction at Cathode: [Ag+ + e- ---> Ag]x2
Oxidation at Anode: Cd ---> Cd2+ + 2e-
2Ag+ + Cd ---> Ag + Cd2+
Is this right?
2IO3- + 12H+ + 5Zn ---> I2 + 6H2O + 5Zn2+
Reduction at Cathode: [Ag+ + e- ---> Ag]x2
Oxidation at Anode: Cd ---> Cd2+ + 2e-
2Ag+ + Cd ---> Ag + Cd2+
Is this right?
2IO3- + 12H+ + 5Zn ---> I2 + 6H2O + 5Zn2+
Answered by
Alex
2Ag+ + Cd ---> 2Ag + Cd2+ *
Answered by
DrBob222
For the cell reactions to occur spontaneously, you have equations written correctly and oxidized/reduced equations also are correct. You have omitted a 5 Zn on the left of the second cell and 5Zn^+2 on the right. But you showed it multiplied by 5; I assume the omission was just an oversight.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.