y = 3*(1.04)^x is an exponential growth formala. The growth factor is 1.04
y = 2 + log(x-3)
y approaches -infinity as x approaches 3 from above. There will be a vertical asymptote at x = 3
What is the amount and type of the growth factor of the model: y=3(1.04)^x
Determine the equation for the asymptote: y=2+ log(x-3)
For the second question, I don't even have an idea what is to be determined.
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