what is the acceleration of a point on the time of a flywheel 0.90 m in diameter, turning at the rate of 1200 rev/min?

Question

what is the acceleration of a point on the time  of a flywheel 0.90 m in diameter, turning at the rate of 1200 rev/min?

drwls · Accepted Answer

1200 rev/min = 20 rev/s = 12.57 rad/s Call that the angular speed, w. The centripetal acceleration is R*w^2. R is the 0.45 m radius. a = 0.45*(12.57)^2 = ___ m/s^2