Question

What is the acceleration of a 32 kg object if a 6.75 N force is applied to it?

Responses

0.21 m/s2

0.21 meters per second squared

4.74 m/s2

4.74 meters per second squared

21.09 m/s2

21.09 meters per second squared

216.00 m/s2

Answer 1

To find the acceleration of an object when a force is applied to it, you can use Newton's second law of motion, which states that:

\[ F = m \cdot a \]

Where:
- \( F \) is the force applied (in newtons),
- \( m \) is the mass of the object (in kilograms),
- \( a \) is the acceleration (in meters per second squared).

We can rearrange this formula to solve for acceleration:

\[ a = \frac{F}{m} \]

Given:
- \( F = 6.75 \, \text{N} \)
- \( m = 32 \, \text{kg} \)

Now, substitute the values into the formula:

\[ a = \frac{6.75 \, \text{N}}{32 \, \text{kg}} \]

Now calculating:

\[ a = 0.2109375 \, \text{m/s}^2 \]

Rounding this to two decimal places gives:

\[ a \approx 0.21 \, \text{m/s}^2 \]

Therefore, the correct response is:

**0.21 m/s²** (or **0.21 meters per second squared**).