What is the acceleration due to gravity at a distance of 1.2 Earth radii above Earth�s surface?

Use M_{Earth} = 5.972 x 10^{24} kilograms
and
r_{Earth} = 6370 km

a_{gravity} =______________{m}{s^2}

2 answers

F = G Mm /R^2
F' = G M m /(1.2R)^2 = G M m /R^2 * 1/1.44

9.81 * 1/1.44 = 6.81 m/s^2
The rest is just to confuse the student by the way.