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What is sin Θ given (3,-2) is a point on the terminal of Θ?

A.-2/3
B.-sqrt13/13
C.3sqrt13/13
D. -2sqrt13/13

I think it's C

1 answer

x^2 + y^2 = r^2

9 + 4 = 13

sin = y / r = -2 / √13 = -2√13 / 13

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