What is an equation of the line that is perpendicular to y + 1 = 1/2 (x - 6) and passes through the point (-3,4)?

Answer choices

y + 3 = -2 (x - 4)
y + 3 = 1/2 (x - 4)
y - 4 = -2 (x + 3)
y - 4 = 1/2 (x + 3)

1 answer

To find the equation of a line that is perpendicular to the given line, we need to find its slope and then change the sign of the slope and flip it to calculate the slope of the perpendicular line. The given line is in the form of y + 1 = 1/2 (x - 6), which can be rewritten as y = 1/2 x - 3.

The slope of the given line is 1/2. The slope of a line perpendicular to this will be the negative reciprocal of 1/2, which is -2.

So, the equation of the line perpendicular to the given line with slope -2 and passing through the point (-3,4) will be of the form y - 4 = -2 (x + 3), which means the option is:

y - 4 = -2 (x + 3)
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