(1/2) m v2^2 = 1.23 (1/2) m v1^2
so
v2 = sqrt(1.23) v1
v2 = 1.11 v1
well, that is an 11% increase
What % increase in momentum if increase of k.e is 23%
A. 46%
B. 33%
C. 50%
D. 11%
E. 46%
4 answers
Thx sir
Answer is correct but I cannot understand formula which you have written.
ke=1/2 m v^2
for ke increase of 23 precent, new KE is 1.23 of original
1.23*1/2 mvi^2=1/2 m v'^2
v'=vi*sqrt 1.23
for ke increase of 23 precent, new KE is 1.23 of original
1.23*1/2 mvi^2=1/2 m v'^2
v'=vi*sqrt 1.23
1 answer