SAGAR

What % increase in momentum if increase of k.e is 23% A. 46% B. 33% C. 50% D. 11% E. 46%

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R2=A2+B2+2ABCos@ = R2=52+102=2.5.10cos120 R2=25+100+100*-0.5 R2=125-50 R2=75 R=8.66 Ans

thanku Sir

W=2pi/T but here T=60 W=2*3.14/60=6.28/60= 0.10rev/s ans

Thx sir

Answer is correct but I cannot understand formula which you have written.

Is 40 ans correct???????????

how we get displacement and distance