PbI2 ==> Pb^+2 + 2I^-
Write Ksp expression.
Plug in Pb^+2, and Ksp, and solve for I^-. A funny way of stating the problem, but the concn of PbI2 equals the concn of Pb^+2.
What [I-] should be maintained in KI(aq) to produce a solubility of 2.0×10−5 mol PbI2/L when PbI2 is added?
2 answers
can you explain that better? i'm confused.
2 answers