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What [PB2+] should be maintained in Pb(NO3) to produce solubility of 1.010^-4 mol PbI2/L when PbI2 (s) is added? Ksp for PbI2 is 7.110^-9

I can't figure it out...

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.........PbI2(s) ==> Pb^2+ + 2I^-
You want PbI2 = 1E-4; therefore, you want Pb^2+ to be 1E-4M

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