What effect would be on the normality of unknown acid? Explain why.

Question

a) if NaOH solution is pipetted into a conical flask containing some distilled water
b) if an air bubble is out from the burette
c) if too much acid is ran out during both titrations although the volumes of acid agreed
with each other

Answer 1

a) Molarity of the NaOH solution would be lower then expected, causing the molarity of the unknown acid calculated to be lower.

b) This would cause you to calculate more volume of the base then actually added. This will cause an increase in the molarity calculated for the unknown acid *** See note at the end.

c) This will cause an increase in the molarity of the acid since the volume of the NaOH will increase.
** See note at the end.

Use the following relationships to reason explanations.

Molarity=moles/volume

M1V1=M2V2

Where

M1=molarity of the acid
V1=volume of the acid
M2=molarity of the base
and
V2=volume of the base

*** I am interpreting this question as an air bubble being seen in the buret. If there is no air bubble in the buret then the results shouldn't be effected.

** I am interpreting this question as using more acid then anticipated.