What are the solutions to the system Y = X + 3x - 4 and y = 2x + 2

Answer 1

To find the solutions to the system of equations Y = X + 3x - 4 and y = 2x + 2, we first need to set the two equations equal to each other.

Since both equations are already equal to y, we can set them equal to each other.

X + 3x - 4 = 2x + 2

Solve for x:

X + 3x - 4 = 2x + 2
X + 3x - 2x = 2 + 4
X + x = 6
4x = 6
x = 6/4
x = 1.5

Now that we have found x, we can substitute it back into either equation to find the value of y:

y = 2(1.5) + 2
y = 3 + 2
y = 5

Therefore, the solutions to the system of equations Y = X + 3x - 4 and y = 2x + 2 are x = 1.5 and y = 5.