they're, not there.
first, factor out the 2 so you have smaller numbers to work with
2(x^2-8x+16) = 0
Now you want two numbers which add to -8 and multiply to +16
-4 and -4 fit the bill, so
2(x-4)(x-4) = 0
Now the answer is clear. x=4 is a double root.
What are the solutions of the quadratic equation?
2x^2 – 16x + 32 = 0
How do I solve this, I'm kinda new to quadratics and there confusing >.>
1 answer
1 answer