To find the solutions to the quadratic equation \((x−7)^2=11\), we first need to solve the equation.
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Take the square root of both sides: \[ x - 7 = \pm \sqrt{11} \]
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This gives us two separate equations to solve:
- \(x - 7 = \sqrt{11}\)
- \(x - 7 = -\sqrt{11}\)
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Solve for \(x\) in each case:
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For \(x - 7 = \sqrt{11}\): \[ x = 7 + \sqrt{11} \]
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For \(x - 7 = -\sqrt{11}\): \[ x = 7 - \sqrt{11} \]
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Now we can identify the two solutions:
- The smaller solution is \(x = 7 - \sqrt{11}\).
- The larger solution is \(x = 7 + \sqrt{11}\).
To approximate these values, we can use \(\sqrt{11} \approx 3.3166\):
- Smaller solution: \(x \approx 7 - 3.3166 \approx 3.6834\)
- Larger solution: \(x \approx 7 + 3.3166 \approx 10.3166\)
Thus, we summarize the solutions:
- The smaller of the two solutions is \(x = 7 - \sqrt{11}\).
- The larger of the two solutions is \(x = 7 + \sqrt{11}\).
So the final answers are:
- The smaller of the two solutions is \(x = 7 - \sqrt{11}\).
- The larger of the two solutions is \(x = 7 + \sqrt{11}\).