If it is 4x^2 - x - 5 = (4x-5)(x+1)
Do you have a typo?
What are the real roots of the quadratic function 4x^2-x+5?
3 answers
no typo. I tried the quadratic equation and got -.986 and 1.24. Does this mean there are no real roots (an option in the question).
Also, for the question 4x^2-12x+9, is the real root (2x-3)?
Also, for the question 4x^2-12x+9, is the real root (2x-3)?
solving 4x^2 - x + 5 = 0
x = (1 ± √-79)/8
which is imaginary.
So there are no real roots.
(How did you get -.986 and 1.24 ??)
For 4x^2 - 12x + 9
it factors to (2x-3)^2
the roots of the corresponding equation ....
4x^2 - 12x + 9 = 0
(2x-3)^2 = 0
x = 3/2
So the real root is 3/2
x = (1 ± √-79)/8
which is imaginary.
So there are no real roots.
(How did you get -.986 and 1.24 ??)
For 4x^2 - 12x + 9
it factors to (2x-3)^2
the roots of the corresponding equation ....
4x^2 - 12x + 9 = 0
(2x-3)^2 = 0
x = 3/2
So the real root is 3/2