Asked by -Untamed-
Determine for what value(s) of d the quadratic equation 5x^2-10x+d = 0 has
i) real and distinct roots
ii)real and equal roots
iii)non-real roots
This is what I did to solve for A.
5x^2-10x+d = 0
b^2-4ac = 0
(-10)^2-4(5)(d) = 0
100-20d = 0
-20d = -100
d = 5
Need help with others.
i) real and distinct roots
ii)real and equal roots
iii)non-real roots
This is what I did to solve for A.
5x^2-10x+d = 0
b^2-4ac = 0
(-10)^2-4(5)(d) = 0
100-20d = 0
-20d = -100
d = 5
Need help with others.
Answers
Answered by
Anonymous
Close. Actually, you solved for (ii).
i) D > 0
100 - 20d > 0
d < 5
ii) D=0
100-20d = 0
d = 5
iii) D < 0
100-20d < 0
d > 5
i) D > 0
100 - 20d > 0
d < 5
ii) D=0
100-20d = 0
d = 5
iii) D < 0
100-20d < 0
d > 5
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