you have the sum of two cubes, so it factors into
(3x+5)((3x)^2-(3x)(5)+5^2)
= (3x+5)(9x^2-15x+25)
It's easy to check that the quadratic has no real solutions. Just use the quadratic formula, learned long ago in Algebra I...
What are the real and complex solutions of the polynomial equation?
27x^3 + 125 = 0
I already got the real solution x = -5/3, I just need to figure out how to find the complex solution. Any help?
1 answer