the answer choices for this question is.
y = -5 and 4
y = 5 and 32
y = 4 and -8
none of the above
what are the excluded values?
y+5/y^2+4y-32
2 answers
again, you should type it as
(y+5)/(x^2 + 4y - 32) , the way you have it, the only division is 5/y^2
= (y+5)/((y+8)(y-4))
so which values would make the denominator zero ?
(y+5)/(x^2 + 4y - 32) , the way you have it, the only division is 5/y^2
= (y+5)/((y+8)(y-4))
so which values would make the denominator zero ?
0 answers