#1 also t=0, since t^2-t = t(t-1)
The original expression must be examined for excluded values.
(t-1)/(t^2-t) = 1/t, so t≠0. But dividing top and bottom by t-1 to get there means that t≠1, because you cannot divide by zero.
#2 huh? There is no x-2 in the denominator.
1/(2x) x≠0
#3
2n / n(n-3) = 2/(n-3), x≠0,3
Same as #1 for logic.
#4
(s+1) / (s+1)(s-5)
s≠-1,5
#5
3(4-x) / (x-4)^2 = -3/(x-4), x≠4
Find any excluded values of each rational expression.
1. t - 1/ t^2 - t
A: Excluded value: 1.
Simplify each rational expression, if possible. Identify any excluded values.
2. 3x^2/6x^3
A: 2x; x ≠ 2
3. 2n/n^2 - 3n
A: ?
4. s + 1/s^2 - 4s - 5
A: ?
5. 12 - 3x/x^2 - 8x + 16
A: ?
1 answer
2 answers