Those would be the values of t for which the derivative f'(t) = 0 is zero,
The derivative is
f'(t) = 2 t^(-1/3) + (5/3) t^(2/3)
That is zero when
(5/6)t^(2/3) = -t(-1/3)
5/6 t = -1
t = -6/5
What are the critical numbers of f(t)=3t^(2/3)+t^(5/3)
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