How do you find the critical numbers and the end points of this function:

Question

f(x)=2x^3-3x^2-12x+5

i calculated the critical numbers as x=-1 and x=2 is this right?!?!

Answer 1

great so far.
now find f(2) and f(-1) for the y values of your critical points.

unless there is a domain given for your x's , there are no "end points" for your function.

Answer 2

If by "ritical numbers" you mean where the function has a local maximum or minimum, that would be where
f'(x) = 6x^2 -6x -12 = 0
x^2 -x -2 = 0
(x+1)(x-2) = 0
yes, -1 and 2 are correct.
f(x) has no end points or absolute maximum or minimum. It goes to + and - infinity when x does the same