2KOH(aq) + H2SO4(aq) -> K2SO4(aq) + H2O(l)
Can you take it from here.
Convert the balanced molecular equation above to an ionic equation; e.g. KOH would be 2K^+*(aq) + OH^-(aq)
H2SO4 would be 2H^+(aq) + SO4^2-(aq)
For the net ionic equation, just cancel ions common to both sides.
What are the correct and accurate products of the following neutralization reaction. Then write the ionic form of the equation and the net ionic form.
KOH + H2SO4 ->
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