What are the coordinates of the vertex of the graph of the function y = -x + 6x - 11

Answer 1

To find the coordinates of the vertex of the graph of the function y = -x^2 + 6x - 11, we first need to determine the x-coordinate of the vertex using the formula x = -b/(2a), where a = -1 and b = 6.

Plugging the values of a and b into the formula, we get:
x = -6 / (2*(-1))
x = -6 / -2
x = 3

Now that we have found the x-coordinate of the vertex, we can substitute this value back into the original equation to determine the y-coordinate.

y = -3^2 + 6*3 - 11
y = -9 + 18 - 11
y = -9 + 7
y = -2

Therefore, the coordinates of the vertex of the graph of the function y = -x^2 + 6x - 11 are (3, -2).