What are the coordinates and radius of the circle whose equation is 2x raise to power 2 plus 2y raise to power 2 plus 4x minus 12y plus 12 equal to zero .
3 answers
The coordinates of the center of the circle are (2, -3). The radius of the circle is 3.
AAAaannndd the bot gets it wrong yet again!
2x raise to power 2 plus 2y raise to power 2 plus 4x minus 12y plus 12
2x^2+4x + 2y^2-12y = -12
(x+1)^2 + (y-3)^2 = 2^2
2x raise to power 2 plus 2y raise to power 2 plus 4x minus 12y plus 12
2x^2+4x + 2y^2-12y = -12
(x+1)^2 + (y-3)^2 = 2^2
Why are you posting this question is the same silly typed way even
after oobleck told you to type it in the normal way??
Also, "What are the coordinates and radius of the circle.." should have said:
What are the coordinates of the centre and the radius of the circle ....
2x raise to power 2 plus 2y raise to power 2 plus 4x minus 12y plus 12 equal to zero
2x^2 + 2y^2 + 4x - 12y - 12 = 0
Add 12 to both sides, then divide each term by 2
x^2 + 2x + y^2 - 6y = 6
complete the square, by adding numbers as show in my next line
x^2 + 2x + 1 + y^2 - 6y + 9 = 6+1+9
(x+1)^2 + (y-3)^2 = 16
then centre is (-1,3) and the radius is 4
btw, as you can see the bot is WRONG again
after oobleck told you to type it in the normal way??
Also, "What are the coordinates and radius of the circle.." should have said:
What are the coordinates of the centre and the radius of the circle ....
2x raise to power 2 plus 2y raise to power 2 plus 4x minus 12y plus 12 equal to zero
2x^2 + 2y^2 + 4x - 12y - 12 = 0
Add 12 to both sides, then divide each term by 2
x^2 + 2x + y^2 - 6y = 6
complete the square, by adding numbers as show in my next line
x^2 + 2x + 1 + y^2 - 6y + 9 = 6+1+9
(x+1)^2 + (y-3)^2 = 16
then centre is (-1,3) and the radius is 4
btw, as you can see the bot is WRONG again