the circle is given by the equation x^2+y^2+8x-7/2y=0

Question

find
(i)coordinates of the centre and the radius
(ii)coordinates of the point where the circle crossesthe x-axis

Answer 1

oh well

x^2 + 8 x = -y^2 + 3.5 y

x^2 + 8 x + 16 = -y^2 + 3.5 y + 16

(x+4)^2 = -y^2 + 3.5 y + 16

y^2 - 3.5 y = -(x+4)^2 + 16

y^2 - 3.5 y + 3.0625 + (x+4)^2 = 19.0625

(x+4)^2 + (y-1.75)^2 = 4.366^2