divide by 72
x^2/24 + y^2/36 = 1
the semi-major axes have lengths √24 and 6
The center is at (0,0), so the candidates are
(±√24,0) and (0,±6)
Now, which of these are the vertices?
What are the co-vertices of the ellipse 3x^2+2y^2=72?
thank you....
2 answers
Is it (0,±6)?
1 answer