What are the advantages of using v= f(L2- L1) rather than using v= 4f L1 ?
3 answers
I have no idea what L2 and L1 are, nor what the function (or variable) f is. You need to explain the situation better.
For the first equation, f is 1020.51Hz, L1 is 8.7cm, and L2 is 24.1cm. For the second equation, f is 428.5Hz and L1 is 19.2cm.
OK, so f is a frequency and you are multiplying it by lengths to get something with a dimension of speed (cm/sec)
The two numbers that you want to compare are not the same. One is 15716 cm/s and the other is 32909 cm/s. I have no idea which is "correct" or more "advantageous" in your situation.
The two numbers that you want to compare are not the same. One is 15716 cm/s and the other is 32909 cm/s. I have no idea which is "correct" or more "advantageous" in your situation.
1 answer