What am i supose to do here?

Question

A chemist performs the following experiment:
2FeCl3 + 3CaCO3 ---> Fe2(CO3)3 + 3CaCl
If he starts with 105g FeCl3 and excess CaCO3 how many grams of CaCl2 will he obtain?

Thanks,
~Nick

Answer 1

how many moles of Iron(III)chloride is 105g? You get 3/2 that number of moles of CalciumChloride. Then convert that to grams.

Answer 2

So is the answer 74.2g? Or did i do something wrong?