We just found that t=27.5. That means the two tanks have an equal amount of water after 27.5 minutes. Now, let's find how much water is in the tanks at that time. Start by substituting 27.5 minutes for t in the expression for Tank A.

Question

Tank A
Liters in Tank A after t minutes: 400+(−3t)
400+(−3· ? )

Answer 1

To find the amount of water in Tank A after 27.5 minutes, we can substitute \( t = 27.5 \) into the expression for Tank A, which is given as:

\[ \text{Liters in Tank A after t minutes} = 400 + (-3t) \]

Substituting \( t = 27.5 \):

\[ \text{Liters in Tank A} = 400 + (-3 \cdot 27.5) \]

Now, calculate \( -3 \cdot 27.5 \):

\[ -3 \cdot 27.5 = -82.5 \]

Now, substitute this value back into the expression:

\[ \text{Liters in Tank A} = 400 - 82.5 \]

Now, perform the subtraction:

\[ 400 - 82.5 = 317.5 \]

Therefore, the amount of water in Tank A after 27.5 minutes is 317.5 liters.