El,
I will get you started here. You have 22% by mass of solute Z(by mass also means w/w), which means 22 g Z/100 g soln.
22 g Z/100 g soln(1 mol Z/215 g Z)x(1.1g/ml)x(1,000ml/L)=?
We have an aqueous solution that contains 22% (by mass) of a hypothetical solute Z. The formula weight of the solute Z is 215 g/mol. The density of the solution is observed to be 1.1 g/mL. What is the molarity of Z in this solution?
2 answers
1.12558