We discussed in lectures that traveling Electromagnetic waves in vacuum of the form
E⃗ =E0xˆcos(kz−ωt),B⃗ =B0yˆcos(kz−ωt)
satisfy all 4 Maxwell's equations. In lectures, I showed that an application of the generalized Ampere's Law (closed loop surrounding area A2, see below), leads to: B0=ε0μ0cE0, and I mentioned that independently it follows from an application of Faraday's Law that B0=E0/c. Combining these two results then leads to the fantastic result that the “speed of light" in vacuum c=1/ε0μ0‾‾‾‾‾√. I want you to show that Faraday's Law indeed leads to the result B0=E0/c. You can show this by choosing a similar special area as we did in lectures:
We define the normal of the surface A1 in the figure above to point in the +yˆ direction. In the following , assume that ℓ=1 m, E0=1 V/m, f=610×1012 Hz, where f is the frequency of oscillation.
(a) We define f1(t)=∮E⃗ ⋅dℓ⃗ , where ∮E⃗ ⋅dℓ⃗ is the closed loop integral taken along the contour of the area A1 in the figure above. Evaluate the function f1(t) in Volts for the following value of t
t=2e-16 sec
(b) Consider the function f2(t)=ϕB(t). Following the method used in Lecture 27, calculate the function f2(t), and evaluate it (in Volts seconds) for the following time t
t=2e-16 sec
(c) Consider again the function f2(t) and evaluate −df2(t)dt in Volts for the following time t
t=2e-16 sec
78 answers
c)0.197142857148
b) any idea for this?
and have you any part of Problems 1 and 2?
And do u have answers for the 4th question?
Anonymous, I have the answers for the 1st and 2nd problems, can u tell me the specific questions for whom u want the answers
Problem 2:
a)?
b)1.5
c)First answer: (n*E_0)/c
d)all 0
Do you have a) and second and third answer for c) phy?
1 c,d
2 a,b
1)b) is 1.5 by the way, if you have slightly different values, make some guesses, it is normally around that value.
with other values it is the same, it must be around that.
dB eB both (E_0/c)*cos(pi/4)
If Phy or someone figures out please let us have it or the formula.
thanks!
0
cos(pi/4)
cos(pi/4)
0
-(E_0/c)*cos(pi/4)
(E_0/c)*cos(pi/4)
0
cos(pi/4)
-cos(pi/4)
0
(E_0/c)*cos(pi/4)
(E_0/c)*cos(pi/4)
PHy can you give the remaining answers for Problem 1 and 2?
2nd prob-
a) Wavelength= 2*pi/k
Frequency= omega/(2*pi)
c) 1.451e8 and
1.6711e8
d) 1.936e8 and
2.229e8
If you want answers of any other probs or formulas, please let me know
1st (g)??
ThE PROBLEM IS WITH b0
Your value did not work for me too.
Could you tell me what the value for k and omega is please Phy?
maybe the value or formula.
I don't get the result with the speed of case 1 and 2.
a)0.89
b)1.34
Rohan, experiment with some guesses if it does not fit, as you can see the number is quite narrow.
I could not figure B_0 out but with your formula managed +-omega in both cases, can you help me with the formula please Rohan?
What is the value of k in radians per meter?
Also what is Q3 part b answer ???
try for a) 0.60 and go up some decimals, 0.62.0.64 etc. it must be around that, because values are not very far away from that.
Do you have Q1) f) B_0 for both cases? value and/or formula Anonymous?
E_0/c
However, I cannot get the result. can anybody work with this or help?
Give pliz somebody formulas on all questions from Q3 and explain as to find B_0 in Q1
d/dt (l (sin((k lambda)/4-t omega)+sin(t omega)))/k where t=2.4*10^-16; omega=3.83*10^15; k=12775810.12; lambda=4.91*10^-7;l=1
Put this value in wolframalpha and divide the result by speed of light
and for Part b: Integrate[Cos[k z - omega t], {z, 0, lambda/4}, {x, 0, l}] where t=2.2*10^-16; omega=3.83*10^15; k=12775810.12; lambda=4.91*10^-7;l=1
Put this value in wolframalpha and divide the result by speed of light
can you maybe help with Problem 1) f) case 2? I cannot get the B_0 for case 2.
A formula and the value, I would be greatful.
1.6711e8 is showing wrong
I don't get it. is this the formula, my speed case value is:200500000
(8.85418782*10^-12)/(200500000)
Is there a mistake with my E_0 value?
how did you calculate step by step? having problems with solution
-((3.83*10^15)/(2.99e8))*integral from 0 to ((4.91*10^-7)/4) of sin(12775810.12*z-3.83*10^15*2.6*10^-16) dz
Could you give us the value, as the formula from X10 did not work for me.
thanks!
formula didn't work, please help!
It does not work with case 1/2 speed, please help!