Asked by Morgan
We did a lab. The reaction of zinc and iodine.
We put 1 g of zinc with 1 g of iodine.. and used alcohol.
Is the equation Zn + I2 ----> ZnI(2)?
The moles of Zn atoms consumed were .003 mol.
The moles of I atoms consumed were .004 mol.
The class got a ratio and we averaged it.. it was 1:1.98
What does this ratio mean? Could someone explain this?
We put 1 g of zinc with 1 g of iodine.. and used alcohol.
Is the equation Zn + I2 ----> ZnI(2)?
The moles of Zn atoms consumed were .003 mol.
The moles of I atoms consumed were .004 mol.
The class got a ratio and we averaged it.. it was 1:1.98
What does this ratio mean? Could someone explain this?
Answers
Answered by
DrBob222
1:1.98 rounds to 1:2 which means the formula is ZnI2.
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